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PDF Let wel

SELECT 

1
2
 
SELECT column_name(s)
FROM table_name

и

1
 
SELECT * FROM

Есть таблица "Persone":

P_IdLanguageNoemnaamAddressStad
1 Hansen Ola Sandnes
2 Svendson Tove Borgvn 23 Sandnes
3 Kari Storgt 20 Stavanger

Итак мы хотим выбрать столбцы "Language"и "Noemnaam".

1
 
SELECT Language,Noemnaam FROM Persone

LanguageNoemnaam
Hansen Ola
Svendson Tove
Kari

Теперь выберем все значения из таблицы "Persone".

1
 
SELECT * FROM Persone

P_IdLanguageNoemnaamAddressStad
1 Hansen Ola Sandnes
2 Svendson Tove Borgvn 23 Sandnes
3 Kari Storgt 20 Stavanger

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